Odds 7 5

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  • Odds conversion table with probability. Must be a number greater than 1. Must be a fraction, for example 2/1. Must be '+' or '-' and a whole number over 100. Must be a number from 0-100. By convention only a set of fractions are used in fractional odds betting markets.

The chance of winning is 4 out of 52, while the chance against winning is 48 out of 52 (52-4=48). Entering A=4 and B=48 into the calculator as 4:48 odds are for winning you get. For 4 to 48 odds for winning; Probability of: Winning = (0.0769) or 7.6923%. Losing = (0.9231) or 92.3077%. Odds are the return you can expect to get if the horse you bet on is successful. It reflects the amount of money bet on a horse; the more money that is invested, the shorter the odds. When horse racing odds are shown in the form of 7-2, 5-1, etc, it expresses the amount of profit to the amount invested.

KUNAL GAURAV 7 years AGO
Odds in favour of event A occurring = Pr(A)/Pr(A')
Odds against event A occurring =Pr(A')/Pr(A)
Probability of occurring event = Pr(A)/[Pr(A)+Pr(A')]
In the question
Pr(A')/Pr(A)=5/7 (Since we are given odds against the event)
So probability of occurring the event = 7/(5+7) = 7/12
Like? Yes (18) No (5)Shubhankur Manuja 7 years AGO
Odd against of a event=(Prob. of Losing)/(Prob. of Winning)
if P is Prob of happening (winning) of event then
=> (1-P)/P = 5/7
=> 7-7P = 5P
=> 12P = 7
=> P = 7/12
Like? Yes (11) No (1)Alok Kumar 7 years AGO
odd against = 5/7 so probability = 7 /12
7/(5+7)
Like? Yes (7) No (2)Mariappan 7 years AGO
5:7 means 5 chance of against and 7 chance of occurrence.Thus prob of occurring is 7/12
Like? Yes (7) No (4)Undapalli Soujanya 7 years AGO
odds aginst=nonoccurence/ occurence;
P(occurence)=occurence/total
Like? Yes (2) No Ankit Shukla 7 years AGO
since the probility odds against any event is =5/12
so the probility of its occurence is=1-(5/12)=7/12
Like? Yes (3) No (1)sanjay singh 7 years AGO
total probability=1
odds against the event=5/12
probability=1-5/12=7/12
Like? Yes (2) No sneha 7 years AGO
against is in the ratio 5:7
so,total sample space is (5+7)=12
against is 5 parts of 12
so probability of occurrence is 7 parts of 12 i.e.,7/12
Like? Yes (2) No Tanu 7 years AGO
(1-p)/p =5/7
p=7/12
Like? Yes (2) No Md Intshamuddin 7 years AGO
Odds AGAINST event = P(not E)/P(E) = 5:7
P(not E)/P(E) = 5:7
=> P(E)=7/12
Like? Yes (4) No (3)rahul jha 7 years AGO
Pr(A')/Pr(A) = 5/7
So probability of occurring of the event = 7/(5+7)
=7/12
Like? Yes (3) No (2)Mayuresh Srivastava 7 years AGO
odds against=prob. of non-occurrence/prob. of occurrence
5/7=(1-p)/p
p=7/12
Like? Yes (1) No Chandni Maurya 7 years AGO
ans=(5). 7/12
odd against a certain event = m:n =5:7
probability of occurrence=n/(m+n)
=7/(5+7)
=7/12
Like? Yes (3) No (2)Raju Sharma 7 years AGO
odd against a event occering =p(a')/p(a)
p(a')=1-p(a) and then p(a')/p(a)=5/7
solving this p(a)=5/12;
Like? Yes (2) No (1)praneeth 7 years AGO
odds against a certain event =p(A')/p(A).we require its occurrence.so,p(A)=7/12.
Like? Yes (1) No Kushal Saraf 7 years AGO
Odds AGAINST event = P(not E)/P(E)
probability of occurence=7/12
Like? Yes (2) No (1)ALOK KUMAR 7 years AGO
ODD AGAINST MEANS P(E')/P(E)=5/7 GIVEN
SO P(E)=P(E)/(P(E)+P(E'))=7/12
Like? Yes (1) No Jagadeesh Rampati 7 years AGO

Odds Are 7 To 5 What Is The Probability

odd against event i.e (1-p)/p=5/7
from above we get p=7/12
probability of occuring an event=7/12
Like? Yes (1) No bindu 7 years AGO
odds against an event is (1-p):p=5:7.so probability of occurrence is 7/12
Like? Yes (1) No ShAg 7 years AGO
odds against = 5:7
i.e. 7/(5+7) = 7/12
Like? Yes (1) No Rishav kuamr 7 years AGO 7.5 pill
odd's against of a certain event is m:n
then probability of not happening a is given by
m/m+n
so probability of a=p(a)=n/m+n
in this question probability of its occurrence is
m=5,n=7
p(a)=7/5+7=7/12
Like? Yes (3) No (3)komal kirti 7 years AGO
odds against=5/7; odd against=p(not E)/p(E);
5/7=(5/12)/x; x=probability of occurance=7/12
Like? Yes (1) No (1)Anil Kumar Bharti 7 years AGO
Exp:
5:7 = 5/7 that means 5/12
Againt odds means : 1-5/12 =7/12 Ans
Like? Yes (1) No (1)richa ahuja 7 years AGO
odds against=unfavourable outcomes/favourable outcomes
odds in favour=fav/unfav
here odds against=5/7
therefore odds in favour=7/5
or probability of its occurrence=7/12
Like? Yes (2) No (2)Harleen Chadha 7 years AGO

7 5 Basketball Player

if odds against an event = m:n
Then the probability of its occurrence = n / (m+n)
Ans: 7/12
Like? Yes (3) No (4)Manikumar R 7 years AGO
7/5+7
Like? Yes (2) No (3)vky 7 years AGO
1-(5/(5+7))
Like? Yes (1) No (2)S.Jenifersmaily 7 years AGO
odds against certain event:p(lossing)/p(winning)
p(A')/p(A)=5/7
probability of occurence=7/(5+7)
=7/12
Like? Yes (1) No (2)

This week, the Raiders become the last AFC West team to get a crack at the New York Jets. The others enjoyed getting a “W” at the expense of the hapless Jets just like every team New York has played this season.

These Jets are a perfect 0-11 this season, which is Hue Jackson-Browns level bad. So, not surprisingly, the Raiders are 7.5-point favorites at the Meadowlands, according to BetMGM. It probably would be more had the Raiders not done a faceplant in Atlanta last week, where they were three-point favorites.

50 1 Odds Payout

Only twice this season have the Jets finished a game with less than an eight-point deficit. Though those games represent two of their last three (Chargers, Patriots), so the Raiders better take these Jets seriously.

Even the Raiders in 2014 only went 0-10. And that season, they had rookie Derek Carr as their excuse. These Jets have former third overall pick Sam Darnold in his third season, so no such excuses exist.

What Are The Odds Calculator

All indications are that Darnold’s days in New York are coming to a close. With their sights set on the No. 1 overall pick, they should have Trevor Lawrence jerseys already in boxes ready to ship. The Raiders hope to do their part to make the Jets’ top pick dreams a reality.